For maths, we have been focusing on using an algorithmic strategy to solve advanced maths problems regarding division. These strategies are called long division and short division. I prefer to use short division because it is more efficient. Some examples of equations we solved with this strategy is 476 ÷ 7 or 823 ÷ 4.
To use short division for an equation such as 217 ÷ 5. First, we see how many times 5 can fit into 2, however this is unable to happen so we expand the number to 21 which includes the 2nd digit of the number. 5 fits into 20 four times, with 1 remaining. You put 4 above the 2nd place value column and you place a small number beside the following digit. That number then becomes 17, so we see how many times 5 can fit into 17. This is able to happen 3 times, with remainder 2. Write how many times 5 can fit into that number and the answer to 217 ÷ 5 becomes 43 remainder 2.
I really enjoyed this maths lesson because I had fun solving hard equations using this strategy and I found it easy because I got used to the thought of using these strategies.
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